¿Cómo se resuelve Log1 + Log2 + Log3 + Log4 + Log5 + Log6 + Log7 + Log8 + Log9 + Log10 a mano, cuando se le da Log 2 = 0.301, log3 = 0.4777 y Log 7 = 0.845?

1 Respuestas


  • Log [1] = 0 Se proporciona el
    registro [2] Se proporciona el
    registro [3]
    Log [4] = Log [2 ^ 2] = 2 * Log [2]
    Log [5] = Log [10/2] = Log [ 10] - Log [2] = 1 - Log [2]
    Log [6] = Log [2 * 3] = Log [2] + Log [3]
    Log [7] se proporciona
    Log [8] = Log [2 ^ 3] = 3 * Log [2]
    Log [9] = Log [3 ^ 2] = 2 * Log [3]
    Log [10] = 1
    Su suma es
      0 + Log [2] + Log [3] + 2 * Log [2] + (1 - Log [2]) + (Log [2] + Log [3]) + Log [7] + 3 * Log [2] + 2 * Log [3] + 1
      = (1+ 2-1 + 1 + 3) * Log [2] + (1 + 1 + 2) * Log [3] + Log [7] + 2
      = 6 * Log [2] + 4 * Log [3] + Log [ 7] + 2

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